PyQt QTest click on QMenu

Question

In my PyQt app I have a main menu, which has the following structure:

Main Menu
|___
    |
    Language
    |       |
    |        Russian
    |       |
    |        English
    Exit

I want to perform a click on Russian to test if the language is changed. I have a link to language_menu in GUI

[...somewhere in MainWindow...]
self.language_menu = QtGui.QMenu()
[....]

so

from PyQt4 import QtGui, QtCore
from PyQt4.QTest import QTest
from gui import MainWindow

class TestMainWindow(unittest.TestCase):

    def setUp(self):
        self.app = QtGui.QApplication([])
        self.ui = MainWindow()

    def tearDown(self):
        self.app.deleteLater()

    def test_translation(self):
        menu = self.ui.language_menu
        rus_lang = menu.actions()[0]
        QTest.mouseClick(rus_lang, QtCore.Qt.LeftButton)

but it tells me that

argument 1 has unexpected type 'QAction'

How do I do this? Is it even possible?

@ekhumoro It worked! Write your comment as an answer and I'll approve it. — GriMel, Feb 14 '16 at 00:21

score 2 · Accepted Answer · answered Feb 14 '16 at 01:11

2

You can use rus_lang.trigger() or rus_lang.toggle() to activate the menu item.

answered Feb 14 '16 at 01:11

ekhumoro

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score 0 · Answer 2 · answered Jan 10 '22 at 19:08

0

i think ekhumoro's answer is wrong because it misses the point of the test, rus_lang.trigger() isnt interacting with the gui.

for me QTest.mouseClick(rus_lang, QtCore.Qt.LeftButton) works fine with QButton maybe QAction has diffrent API.

answered Jan 10 '22 at 19:08

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PyQt QTest click on QMenu

2 Answers2