I am working in Linux and trying to execute a C program with setuid
on Linux. Here is my code:
#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <errno.h>
int main()
{
int ret;
fprintf ( stderr, "Orig: %d Effective: %d\n", getuid(), geteuid() );
ret = setuid ( 122 );
if ( ret < 0 )
{
perror ( "Problem in setuid " );
return ( 1 );
}
fprintf ( stderr, "UID : %d Effective: %d\n", getuid(), geteuid() );
execlp ( "/bin/id", "/bin/id", NULL );
fprintf ( stderr, "Problem executing execlp\n" );
return ( 0 );
}
Upon execution, the UID is not changed. The output is:
[hauschild@hoare7 ~]$ ~sanjiv/bin/a.out
Orig: 155 Effective: 122
UID : 155 Effective: 122
uid=155(hauschild) gid=100(users) euid=122(sanjiv) groups=100(users)
[hauschild@hoare7 ~]$
I have looked at other questions in SO but unable to figure this one out. The permissions on executable are rwsr-sr-x
. Notice how the code runs to completion and the exit status is reported as 0
. However, when I run it through strace
, it gives me an error on setuid
and exists with a 1
. as follows:
geteuid() = 155
getuid() = 155
write(2, "Orig: 155 Effective: 155\n", 27Orig: 155 Effective: 155
) = 27
setuid(122) = -1 EPERM (Operation not permitted)
write(2, "Problem in setuid : Operation n"..., 45Problem in setuid : Operation not permitted
) = 45
exit_group(1) = ?
+++ exited with 1 +++
Can anyone see what I could be doing wrong?