How to access to parent widget on qt?

Question

I have an inherited QTreeWidget (called PackList) class and its parent is a KXmlGuiWindow. How can I access to the parent's slots?

I've tried getParent()->mySlot() from the QTreeWidget class but I've got

error: no matching function for call to 'PackList::mySlot()'

Does anybody know the correct way? Thanks

score 15 · Accepted Answer · answered Dec 11 '08 at 02:21

15

If you know the parent's class, you will have to cast parentWidget() to that class and then call your slot. Keep in mind whether or not it's a slot makes no difference in this case. You are just calling a method.

((KXmlGuiWindow*)parentWidget())->mySlot();

You can make the call without casting by wiring up your signal to the slot.

connect( this, SIGNAL(mySignal()), parentWidget(), SLOT(mySlot()) );

Lastly, you can use QMetaObject::invokeMethod to call it if you don't want to cast it. That's probably overkill.

answered Dec 11 '08 at 02:21

Michael Bishop

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This is the correct way to do it. I have used it without typecast `parentWidget())->setEnabled();` and I override the parent's setEnabled function. And then, my modification did not work. well, I realized later that this is so silly mistake, but I think it can be a point many fellows may waste their time. anyway; DO NOT FORGET THE TYPECAST. – meakgoz Oct 14 '15 at 09:43

score 1 · Answer 2 · answered Dec 09 '08 at 14:16

1

I'm not sure I fully understand your question.

However, you can access the parent widget of a widget with parentWidget().

Then, you should be able to call any public slot :

parentWidget()->a_slot();

answered Dec 09 '08 at 14:16

Jérôme

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solved connecting the event in the parent instead than the packList – JuanDeLosMuertos Dec 09 '08 at 14:33

How to access to parent widget on qt?

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