gulp watch TypeError: glob pattern string required

Asked Feb 05 '16 at 16:06

Active Feb 05 '16 at 16:18

Viewed 469 times

I've .po files in my application. I've created a watch to see when the translations file have been changed and compile them

gulp.task('translations', () => gulp
  .src('po/.*po',) 
  .pipe(gettext.compile({format: 'json'}))
  .pipe(gulp.dest('dist/translations/')));
)

gulp.task('watch', () => {
  gulp.watch('po/**/*.po', ['translations']);
});

I use poedit if I do some change it works, but if I just click save button without a new change the gulp process die throwing the error TypeError: glob pattern string required

Update

I've changed gulp.watch for gulp-watch package and it throws me better info

ENOENT: no such file or directory, stat '/home/rkmax/Development/MyProject/po/es_ES.temp.po'

edited Feb 05 '16 at 16:18

asked Feb 05 '16 at 16:06

rkmax

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A full stack trace would be helpful, but it sounds like a bug with either gulp watch or poedit. – helion3 Feb 05 '16 at 16:08
@helion3 I've updated the question with more info. there's some way I can ignore that temp.go files – rkmax Feb 05 '16 at 16:18
@rkmax: You can negate/ignore files with the `!` character in your globs. So try, using `['po/**/*.po', '!po/**/*.temp.po']` – hamstu Feb 05 '16 at 20:37
No luck. still throwing the same error – rkmax Feb 05 '16 at 21:14

gulp watch TypeError: glob pattern string required

Update

0 Answers0