Performing assertions on multiple properties of a Class

Question

I know from the docs I can do this ...

result.Should().BeOfType<MyClass>().Which.Property1.Should().Be("String")

Is there a way I can test multiple properties, in a way similar

result.Should().BeOfType<MyClass>().Which.Property1.Should().Be("String").And.Property2.Should().Be(99);

It's also be good if it were possible to do either of the above tests without having to assert hat they are 'OfType' but I suspect that there is no other way for the code to know what properties are available.

score 5 · Accepted Answer · answered Feb 03 '16 at 17:55

5

You can do a structural comparison assertion against an anonymous type, like this:

result.ShouldBeEquivalentTo(new { Property1 = "String", Property2 = 99 }, options => options.ExcludingMissingMembers());

answered Feb 03 '16 at 17:55

Dennis Doomen

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Nice one. Am liking this more and more. – Stuart Hemming Feb 03 '16 at 18:36
Though it is nice, the problem I see with this solution that it is not strongly typed. – shlomiw Apr 09 '17 at 12:00
2

You can chain it with `result.Should().BeOfType().And.ShouldBeEquivalentTo(....` – Dennis Doomen Apr 11 '17 at 18:41

score 2 · Answer 2 · answered Oct 08 '20 at 14:10

One simple solution is to use the AndWhichConstraint type returned by BeOfType<>().

This is what I end up doing:

var myClassType = result.Should().BeOfType<MyClass>;
myClassType.Which.Property1.Should().Be("String");
myClassType.Which.Property2.Should().Be(99);

Performing assertions on multiple properties of a Class

2 Answers2