Error with C++ partial specialization of template

Question

I am using PC-Lint (great tool for static code analysis - see http://www.gimpel.com/) For the following chunk of code:

class ASD {
    protected:
        template<int N>
        void foo();
};

template<>
inline void ASD::foo<1>() {}

template<int N>
inline void ASD::foo() {}

PC-lint gives me a warning:

inline void ASD::foo<1>() {}
mysqldatabaseupdate.h(7) : Error 1060: protected member 'ASD::foo(void)' is not accessible to non-member non-friend functions

I believe the code is fine and the error is on the lint side, but I think Lint tool is REALLY great tool and it's more likely than I don't know something. So is this code OK?

score 2 · Answer 1 · answered Aug 18 '10 at 13:48

2

You have only one function foo in your struct ASD and it is in the protected section. It is not accessible from non-member functions. At the same time struct ASD doesn't have any other member functions. So nobody have access to foo, I believe this is the reason for that error message.

Try to change your struct to the following, for example:

class ASD {
    public:
        void bar() { foo<1>(); }
    protected:
        template<int N>
        void foo();
};

answered Aug 18 '10 at 13:48

Kirill V. Lyadvinsky

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1

But wouldn't any arbitrary child classes have access to the `foo` function? – Mark B Aug 18 '10 at 14:03
In this example, and I believe in the code which produces the error there are no child classes. – Kirill V. Lyadvinsky Aug 18 '10 at 14:15
Try adding a virtual function to the class. It may do a trade-off here. – Johannes Schaub - litb Aug 18 '10 at 18:21

score 1 · Accepted Answer · answered Sep 16 '10 at 14:14

1

The bug was in PC-Lint itself. It has been fixed in the newest version.

answered Sep 16 '10 at 14:14

ssobczak

1,795
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Error with C++ partial specialization of template

2 Answers2