ServletContext#getRealPath(File.separator) giveing null in tomcat

Question

I use following code in HttpServlet.

String pathToWeb = getServletContext().getRealPath(File.separator);

I have application where above code is working fine and return the real path of application directory. Whereas I send another branch for QA and not able to detect the real-path using above code.

which is always return null, using java8,tomcat8 on windows server. Please assist.

I already gone through question like this but not able to find out the solution.

@wero, the path to application folder. – Amol Patil Jan 28 '16 at 07:52 — Amol Patil, Jan 28 '16 at 07:52
@wero, yes I am on windows server – Amol Patil Jan 28 '16 at 07:54 — Amol Patil, Jan 28 '16 at 07:54

score 1 · Accepted Answer · answered Jan 28 '16 at 07:56

1

Use / for the path of the context root:

getServletContext().getRealPath("/")

instead of the OS-specific file separator.

answered Jan 28 '16 at 07:56

wero

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ServletContext#getRealPath(File.separator) giveing null in tomcat

1 Answers1