Can't explode a method in php

Asked Jan 23 '16 at 14:08

Active Jan 23 '16 at 14:10

Viewed 89 times

What do I missed in my code ? I tried to explode/split a method but the result is empty array. Here's my code:

function fileName($id){
  $result = mysql_query("SELECT * FROM folders WHERE folder_id = ".$id."");
  $row = mysql_fetch_array($result);
  if($row['parent'] != 0){
      echo $row['folder_name']."_";
      fileName($row['parent']);
  }else{
      echo $row['folder_name'];
  }
}
if(isset($_POST['upload'])){
  $count = $_FILES['files']['name'];
  $N = count($count);
  $nama = fileName($_POST['folders']);
  $ex = split("\_", $nama);
  echo "<p>";
  var_dump($ex);
}

the result:

Jack_Doyou_Uploaded

array(1) { [0]=> string(0) "" }

edited Jan 23 '16 at 14:10

u_mulder

54,101
5
48
64

asked Jan 23 '16 at 14:08

Hendrik Eka

4

your fileName-function does not return anything. – Franz Gleichmann Jan 23 '16 at 14:10
1

If you want to split by `_` - use it and not `\_` – u_mulder Jan 23 '16 at 14:10
@u_mulder still doesn't work .. – Hendrik Eka Jan 23 '16 at 14:21
@FranzGleichmann I'm a bit confused how to return my function.. – Hendrik Eka Jan 23 '16 at 14:22
@Hendrik Eka via the [return](http://php.net/manual/en/function.return.php)-statement, which is a basic element of any programming language with functions – Franz Gleichmann Jan 23 '16 at 14:24
@FranzGleichmann yeah I know that, but what variable that I need to return ?? – Hendrik Eka Jan 23 '16 at 14:26
Thanks, I've found the way.. – Hendrik Eka Jan 23 '16 at 17:17

Can't explode a method in php

0 Answers0