How many NA or NaN in a list?

Question

Suppose I have a list:

set.seed(123)
n <- 4
lis <- list(
 m1 = matrix(nrow=n,ncol=n,data=sample(c(NA, 1:10), n*n, TRUE)), 
 m2 = matrix(nrow=n,ncol=n,data=sample(c(NA, 1:10), n*n, TRUE))
  )

I want to know how many NA (NaN) we have in this list?

`NA` is different than `NaN`, Do you want the joint response of both concepts? — PereG, Jan 21 '16 at 15:52
@PereG `NaN` is captured by `is.na()`. Try `is.na(sqrt(-1))` — RHertel, Jan 21 '16 at 15:54

score 6 · Accepted Answer · edited Jan 21 '16 at 15:52

6

This could be simpler:

sum(is.na(unlist(lis)))

edited Jan 21 '16 at 15:52

Frank

66,179
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answered Jan 21 '16 at 15:50

RHertel

23,412
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1

Thank you, @Frank for correcting the parentheses :-) – RHertel Jan 21 '16 at 15:53

score 2 · Answer 2 · answered Jan 21 '16 at 15:47

2

sum(sapply(lis, function(i) sum(is.na(i))))
[1] 2

answered Jan 21 '16 at 15:47

fdetsch

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How many NA or NaN in a list?

2 Answers2