I need to verify if opening the browser url is not landing to a particular page. Code snippet is a as below, where open is performed and the page displays 'couldn't open this url' but still exception is thrown from selenium
Error:
"ERROR in invoking Selenium Commands:Timed out after 100000ms".
Selenium RC command
selenium.setTimeout("100000");
selenium.open(url);
How to verify negative url's via selenium
To open url in web browser
String browser = "firefox";
//String browser = "chrome";
//String browser = "ie";
@Test
public void googleSearch() {
WebDriver driver = null;
if (browser.equalsIgnoreCase("chrome")) {
System.setProperty("webdriver.chrome.driver", "path-to-chromedriver\chromedriver.exe");
driver = new ChromeDriver();
}
else if(browser.equalsIgnoreCase("ie")){
System.setProperty("webdriver.ie.driver","path-to-IEdriver\IEdriver.exe");
driver = new InternetExplorerDriver();
}
else {
driver = new FirefoxDriver();
}
driver.manage().timeouts().implicitlyWait(40, TimeUnit.SECONDS);
driver.manage().window().maximize();
driver.get("http://www.google.com");
}
It could be achieve to get the HTTP status code of requested URL but selenium does not support to get HTTP status code (like 400, 500).
Other approach would be:-
--> Open URL
--> Put assertion for valid text on the page. (It will return fail if URL is invalid else URL is valid)
