opendir warning acces denied, shows two params instead of one

Asked Jan 20 '16 at 09:52

Active Jan 20 '16 at 10:05

Viewed 170 times

i have just silly question. When i have this code in PHP

$dirResult = opendir($pathReal);

where path real is string contains path to file, i get error

Warning: opendir(\149.223.22.11\cae\04_Knowledge-base,\149.223.22.11\cae\04_Knowledge-base): Access is denied.

I know, that issue is with user rights in path im trying to acces, thats clear. But what concerns me is why in warning is opendir parameter written twice?

I would expect warning like this

Warning: opendir(\149.223.22.11\cae\04_Knowledge-base): Access is denied.

but nop. Also i double checked input value, and it seems correct to me. Normal string value with only one path parameter.

edit:

Also when i take a look at next warning Warning: opendir(\149.223.22.11\cae\04_Knowledge-base): failed to open dir:

there is opendir param only one, what seems correct to me :)

edited Jan 20 '16 at 10:05

asked Jan 20 '16 at 09:52

Luboš Suk

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if there is permission issue. give permission chmod -R 777 [file] – Monty Jan 20 '16 at 10:02
yeah, i what issue is, but im curious about warning message. I will try to edit question to be more transparent – Luboš Suk Jan 20 '16 at 10:03
Warnings are not important. if you got answer from my prev comment then i am putting it in answer. – Monty Jan 20 '16 at 10:10
1

Probably just a faulty generation of the warning message by PHP … – CBroe Jan 20 '16 at 10:12
check permissions by `int fileperms ( string $filename )` http://php.net/manual/en/function.fileperms.php – Szymon Roziewski Jan 20 '16 at 10:14

opendir warning acces denied, shows two params instead of one

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