Using regular expression in express router

Question

attempting to match the following router

# GET /measurements/2013-10-10T16:20:00.000Z

Currently using this code:

var router = express.router();
router.get(/measurements\/:date(.*Z$), ResultCtrl.processRequest)

what am I missing here ?

Take a look at http://stackoverflow.com/questions/10858005/regex-for-route-matching-in-express — Nicholas, Jan 17 '16 at 20:08
this did the job..router.get(/measurements\/(\d{1,4}.+[zZ]$)/, MeasurementCtrl.getBasedOnISODate); — runtimeZero, Jan 18 '16 at 15:06

Nicholas · Answer 1 · 2016-01-17T22:05:50.007

1

Try

router.get('/measurements/:date(^\d{4}-\d\d-\d\dT\d\d:\d\d:\d\d\.\d{3}Z$)', ResultCtrl.processRequest)

That will match a timestamp of the form ####-##-##T##:##:##.###Z, where each # is a digit.

edited Jan 17 '16 at 22:05

answered Jan 17 '16 at 20:10

Nicholas

i got that.. wanted something more specific – runtimeZero Jan 17 '16 at 20:11
More specific how? A more specific regex, you mean? – Nicholas Jan 17 '16 at 20:12
Perhaps `/^\d{4}(?:-\d{2}){2}T(?:\d{2}:){2}\d{2}\.\d{3}Z$/` – Nicholas Jan 17 '16 at 20:18

1 Answers1