array_splice() is not working as expected

Question

Some help please with this thing that was confused me about the correct use of array_splice(); When i copy literally the following code from the php.net website, that appears as follow:

$input = array("red", "green", "blue", "yellow");
array_splice($input, 2);
// $input is now array("red", "green")

But on my localhost, the result is not as shown in the website example. I got this:

Array ( [0] => blue [1] => yellow )

What happens here?

Resource http://php.net/manual/en/function.array-splice.php

I have been tested the same code on [phpfiddle.org](http://phpfiddle.org) but the result is not as the expected in php.net. — user5782629, Jan 17 '16 at 19:47
That's right @CharlotteDunois I understend now the correct use of this function. Thank you, thanks all! — user5782629, Jan 17 '16 at 20:04

score 0 · Answer 1 · answered Jan 17 '16 at 19:47

0

This is correct. The return array will contain removed elements, i.e. ( "red", "green" ). The original array will be modified to contain the elements which were not removed, i.e. ( "blue", "yellow" ).

answered Jan 17 '16 at 19:47

Zbynek Vyskovsky - kvr000

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Well, then that is a documentation problem of [php.net](http://php.net)? if so, then all examples are wrong!! – user5782629 Jan 17 '16 at 19:53
@user5782629 No, the return value of `array_splice` contains the removed elements. `$input` has the not removed ones. – Charlotte Dunois Jan 17 '16 at 19:56

array_splice() is not working as expected

1 Answers1