destructure a parameter and keep reference to it too

Question

Is there a way in ES6 to destructure a parameter and reference it by name as well?

myfunction(myparam) {
    const {myprop} = myparam;
    ...
}

Can this be done in a single line in the function parameter list? Something similar to Haskell's @ in pattern matching.

You are destructuring `myparam` and you can still access it, right? I don't get the question. — thefourtheye, Jan 15 '16 at 16:14
yes. I am asking about the syntax. I know how to accomplish what I need using various ways. I just was wondering if this can be done in a single line. — akonsu, Jan 15 '16 at 16:15
@thefourtheye: Something like `myfunction(obj@{myprop})`. You can do this in LiveScript like `f = ({myprop}:obj)` for example. — elclanrs, Jan 15 '16 at 16:16

Felix Kling · Accepted Answer · 2016-01-15T17:44:59.497

3

There is no syntax support for this. I guess you could hack around this with something like:

const myFunction = (function() {
  function myFunction(myparam, {myprop}) {
    // ...
  }

  return function(myparam) {
    return myFunction(myparam, myparam);
  };
}());

or even

function myFunction(myparam, {myprop}=myparam) {
  // ...
}

but both may be considered too hacky.

edited Jan 15 '16 at 17:44

answered Jan 15 '16 at 17:15

Felix Kling

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destructure a parameter and keep reference to it too

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