Pass Values from a DataGridView into a seperate Form

Question

What I am trying to do is when a user double clicks on a row a separate form will pop up. Then populates the the TextBoxes in the new form with values from the DataGridView. I can get the Form to appear from a double click, after that im not sure what to do? My code :

private void dgvTable_CellContentDoubleClick(object sender, DataGridViewCellEventArgs e)
{
    FrmInfo frmInfo = new FrmInfo();

    frmInfo.ShowDialog();
    frmInfo.Dispose();
    var notes = dgvTable.Rows[e.RowIndex].Cells["Notes"].Value;   
}

Thanks

I dont know what code you have so far, but couldn't you create a constructor for the new form which takes the needed data from the dataGridView as parameters, and create the form using that constructor on the double click event? — spersson, Jan 13 '16 at 14:06
Possible duplicate of [Send values from one form to another form](http://stackoverflow.com/questions/1559770/send-values-from-one-form-to-another-form) — stuartd, Jan 13 '16 at 14:08

Ahmed Suror · Accepted Answer · 2016-01-13T14:45:21.490

It's Easy! First of all you can't reach other forms controls in c# in the normal way that vb.net does, so you can do the following:

Preparing form to receive data:

1- In the form constructor void add parameters to handle the received data.

2- After the InitializeComponent(); void add the lines of code like below:

public frm1(string txt1, string txt2, string txt3)
{
     InitializeComponent();
     textBox1.Text = txt1;
     textBox2.Text = txt2;
     textBox3.Text = txt3;
}

Handle the datagridview dg_RowHeaderMouseDoubleClick event:

-Note: you can also handle the CellDoubleClick event in your example, but my event is make more sense.

1- Create variables to hold the sent data.

2- Create a new form instance for the form that will handle the data and pass the row cells data to the method parameters in the exact desired order.

private void dg_RowHeaderMouseDoubleClick(object sender, DataGridViewCellMouseEventArgs e)
{
    //Collect the row cells values:
    string val1 = dg.Rows[e.RowIndex].Cells[0].Value.ToString() //data of the first cell in the row
    string val2 = dg.Rows[e.RowIndex].Cells[1].Value.ToString() //data of the second cell in the row
    string val3 = dg.Rows[e.RowIndex].Cells[2].Value.ToString() //data of the third cell in the row
    //Initialize a new instance of the data handle form and send the row data to it:
    var newFrm = new frm1(val1, val2, val3);
    newFrm.Show();                
}

And so on, you can create as many parameters as you can.

Thanks, put im stuck on your step 1? can you give an example — AndroidAL, Jan 13 '16 at 15:23
@AndroidAL In the form that will have the textboxes -frmInfo in your example- view the code of it, you should see in the top a void like: `public frmInfo()` this is the form constructor, modify it like the answer: `public frmInfo(string txt1, string txt2, string txt3)` Try and reply... — Ahmed Suror, Jan 13 '16 at 15:43

Pass Values from a DataGridView into a seperate Form

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