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Starting from a circuit I'm able to obtain simplified the boolean expression:

F(A,B,C,D) = A'D' + ABC + BCD'

After observing the k-map I can observe that the expression BCD' (green) is covered by A'D + ABC.

k-map of F(A,B,C,D)

How can I factor out BCD' mathematically?

ctrlbox
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    I'm voting to close this question as off-topic because it's not programming related (is it **that** hard to read [ask]??) – Amit Jan 12 '16 at 22:08
  • Thanks for being helpful, Amit. I apologize if this question isn't directly programming related. I know a lot of programmers are knowlegdeable on this topic, and most are very helpful, so I gave it a try. – ctrlbox Jan 12 '16 at 22:12
  • Maybe, but there are reasons why this (and every other q&a site) has rules, guidelines and list of relevant topics. Please don't abuse this resource. – Amit Jan 12 '16 at 22:17

1 Answers1

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Use the consensus theorem

XY + X'Z + YZ =  XY + X'Z

A'D' + ABC + BCD' = A'D' + ABC

with BCD' being a redundant term

gehbiszumeis
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Rachel
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