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I'm building a blog and I want my categories to have beautiful URL's like blog/music, blog/art, etc.

So far, I've managed to make them look like this

/blog?category=music

class Article < ActiveRecord::Base
  belongs_to :category

  extend FriendlyId
  friendly_id :title, use: :slugged

  scope :by_category, -> (slug) { joins(:category).where('categories.slug = ?', slug) if slug }
end

-

class Category < ActiveRecord::Base
  has_many :articles

  extend FriendlyId
  friendly_id :name, use: [:slugged, :finders] 
end

view

= active_link_to category.name, articles_path(category: category.slug), remote: true,
     class_active: 'active', class_inactive: 'inactive', wrap_tag: :dd, active: /#{Regexp.escape(category=category.slug)}/

controller

Article.by_category(params[:category])
Billy Logan
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  • As I can see, you have overhead. Why you using scope when you can get articles just like that `Category.find(params[:category]).articles` ? – axvm Jan 12 '16 at 21:00

2 Answers2

1

You don't need friendly_id for this task

add something like this to your routes:

  get 'blog/:category', to: 'articles#index', as: "category"

and then

 link_to category, category_path(category)

http://guides.rubyonrails.org/routing.html

kirqe
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1

You need friendly_id only to create slugs based on title of the category. If you want to make slug unique in scope of category you can use special friendly_id module to solve this problem.

To make nice nesting in url you can do something like this in your routes:

get 'blog/:category', to: 'articles#index', as: "category"

Something like this in your articles controller:

class ArticlesController < ApplicationController
  def index
    @category = Category.friendly.find(params[:category])
    @articles = @category.articles
    respond_to do |format|
      # and so on...
    end
  end
end

And something like this in your views:

link_to category.title, category_url(category)
kimrgrey
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