Python: Converting inches to feet

Question

I thought if I made the numbers float that it would give me a number with a decimal.

height = 65.0 / 12.0
print height

What I get back is 5 without the remainder when I use it in a string. Like say:

    print "He is %d tall." % height

I'm actually using it in a string with %d but all it prints is 5 in the string. I did it like I did above and it worked. So it looks like a dumb question. — pynoob00, Jan 09 '16 at 22:05

Benjamin · Answer 1 · 2016-01-13T21:03:45.910

If you want to stick to the %-formatting use %g to get the decimal places:

In [5]: print("He is %g tall." % height)
He is 5.41667 tall.

You could also define the number of decimal places (e.g. 2 places) like this %.2f:

In [13]: print("He is %.2f tall." % height)
He is 5.42 tall.

The pythonic way to format, however, would be:

In [14]: print("He is {0:.2f} tall.".format(height))
He is 5.42 tall.

EDIT:

cricket_007 is right: OP is using Python2. Thus the correct syntax would be:

print "He is {0:.2f} tall.".format(height)

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