Photon's answer is very good: he suggested alongated vertical edge filters to capture the vertical edges of the streaks.
However, if you are interested in locating the streaks themselves and not their edges, you might consider a slightly different approach:
I propose to, first, eliminate the "DC" component, so that the streaks will "pop out" of a roughly constant background, then use a vertical sum
to locate them and produce a mask.
Here's a sketch of the code:
img = im2double( imread('https://i.stack.imgur.com/SqZrf.jpg') ); %// read the image
Use a horizontal filter to get an estimate of the local "DC", that is, an image where the streaks are gone:
dc_est = imfilter(img, ones(1,31)/31, 'symmetric' );
Looking at the difference between the image and the estimated "DC" should make the streaks pop out and easy to threshold using a global threshold:
global_thr = 0.025;
mask = ones(size(img,1),1)*(mean(img-dc_est,1)>global_thr);
figure; imshow(mask);
And heres' the result (you might want to change the threshold value and see how it affects the result):

The estimated "DC", dc_est
looks like:

If you are after a more elaborate adventure, I recommend that you explore this work: I. Horev, B. Nadler, E. Arias-Castro, M. Galun, R.Basri
Detection of long edges on a computational budget: a sub-linear approach
(SIAM 2015). This method is aimed at finding these elusive edges and ridges in noisy intensity images.