Define a region in using MaxValue[] function in Mathematica

Question

The following two gives completely different output from Mathematica. The online document does not seem to require a pair of curly braces. https://reference.wolfram.com/language/ref/MaxValue.html

Tau = 10;
Diff = 1/3;
phi[tau_] := 0.5 Sin[Pi tau/(Tau + 2 Diff)] + 0.5 Sin[Pi (tau + 2 Diff)/(Tau + 2 Diff)];
In[1]=MaxValue[phi[tau], {tau} \[Element] Interval[{0.0, 10.0}]]
In[2]=MaxValue[phi[tau], tau \[Element] Interval[{0.0, 10.0}]]

Output:

Output[1]=0.995185

MaxValue::objfs: The objective function {0.5 Sin[(3 \[Pi] Subscript[tau, 1])/32]+0.5 Sin[3/32 \[Pi] (2/3+Subscript[tau, <<1>>])]} should be scalar-valued. >>

Out[2]=MaxValue[0.5 Sin[(3 \[Pi] tau)/32] + 0.5 Sin[3/32 \[Pi] (2/3 + tau)], tau \[Element] Interval[{-2.22507*10^-308, 10.}]]

Are you saying that the brace set is necessary, but omitted in the document? — user2008151314, Dec 30 '15 at 19:35
the docs don't give any example of a single variable `MaxValue` / `Element` usage. Evidently the brackets are required and the docs should say so. — agentp, Dec 31 '15 at 15:46

Edmund · Answer 1 · 2016-01-03T02:49:39.580

1

The documentation does specify that you need curly braces when using the region specification method to define the constrains. In the Details and Options section fourth method of defining constraints with a region specification shows that the curly brackets are necessary.

Hope this helps.

edited Jan 03 '16 at 02:49

answered Jan 03 '16 at 02:44

Edmund

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Good catch! Thanks! Apparently this is not documented consistently everywhere. – user2008151314 Jan 04 '16 at 04:06

Define a region in using MaxValue[] function in Mathematica

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