A way to do this could stripping every unwanted character from the String and then check it's length. This could look like this:
public static void main(String[] args) throws Exception {
final String sentence = " Hello, this is the 1st example sentence!";
System.out.println(countletters(sentence));
}
public static int countletters(String sentence) {
final String onlyLetters = sentence.replaceAll("[^\\p{L}]", "");
return onlyLetters.length();
}
The stripped String looks like:
Hellothisisthestexamplesentence
And the length of it is 31.
This code uses String#replaceAll
which accepts a Regular Expression and it uses the category \p{L}
which matches every letter in a String. The construct [^...]
inverts that, so it replaces every character which is not a letter with an empty String.
Regular Expressions can be expensive (for the performance) and if you are bound to have the best performance, you can try to use other methods, like iterating the String, but this solution has the much cleaner code. So if clean code counts more for you here, then feel free to use this.
Also mind that \\p{L}
detects unicode letters, so this will also correctly treat letters from different alphabets, like cyrillic. Other solutions currently only support latin letters.