How to convert string to hex in unpacked BCD format?

Question

I want to convert the String Entered convert into BCD.

a = '2015'
''.join(format(int(c), '04b') for c in str(int(a, 16)))

is giving me '1000001000010011'. But I want it to read 0010 0000 0001 0011 as in unpacked BCD format. Can anyone help me with this?

Can you explain what encoding is `'\x20\x15'` to `'2015'` ? That's not hex and not BCD — Seif, Dec 24 '15 at 11:40
@Kasramvd Basically I want to import this number in hex to the microcontroller. The number has been entered with `a = raw_input("Enter no.")` — abhi1610, Dec 24 '15 at 12:09
@Rockybilly I know it is BCD string but I want to convert it to unpacked BCD. As in digitwise BCD. — abhi1610, Dec 24 '15 at 12:12
Don't you additionally need a `C` or `D` or `F` for the sign? — Marichyasana, Dec 24 '15 at 13:25
I can't get your question. `int('0011', 2)` is 3, not 5 (your last digit). — GingerPlusPlus, Dec 24 '15 at 13:37

Rockybilly · Accepted Answer · 2015-12-24T13:26:38.243

2

My friend, as you see, clearer the question make, easier for us to help you.

Here how I managed your problem

no = "2015"
bcd = " ".join(["0"*(4 - len(bin(int(number))[2:])) + bin(int(number))[2:] for number in no])

print bcd

# 0010 0000 0001 0101

0010 0000 0001 0011 was your output and it is wrong. So your issue is not just the spaces between 4-digit representation. However, to resolve it:

The issue of spaces was because of the

''.join()

you used. You needed

' '.join()

instead.

edited Dec 24 '15 at 13:26

answered Dec 24 '15 at 13:18

Rockybilly

1 Answers1