How to generate random numbers in Swift 2 Xcode 7?

Question

Have updated to Xcode 7, which has Swift 2. I am creating an app. I need to generate random numbers. In Swift, there used to be arc4random(). But in Swift 2, arc4random() is not there. Instead, I am getting:

 arc4random_addrandom(<#T##UnsafeMutablePointer<UInt8>#>, <#T##Int32#>)
 arc4random_stir()
 arc4random_buf(<#T##UnsafeMutablePointer<Void>#>, <#T##Int#>)

How do I now generate random numbers? Any help would be appreciated a lot.

`rand()`, `rand_r(UnsafeMutablePointer)`, or `random()`, maybe. — holex, Dec 17 '15 at 09:16
Also discussed in the Apple Forum: https://forums.developer.apple.com/thread/15643. — Martin R, Dec 17 '15 at 09:21

score 3 · Answer 1 · answered Dec 17 '15 at 09:16

3

arc4random() and arc4random_uniform(_:) are actually there, they're just not autocompleting for some reason. You can still use them!

answered Dec 17 '15 at 09:16

jtbandes

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I actually tried both but it is giving me an error : 'Expected pattern'. Now what shall I do? – ojassethi Dec 17 '15 at 09:20
What code exactly gives you this error? `let x = arc4random()` or `let x = arc4random_uniform(42)` work for me. – jtbandes Dec 17 '15 at 09:20
i tried : var random : Int = Int(arc4random() % 2) – ojassethi Dec 17 '15 at 09:24
If you want a number that's either 0 or 1, you should use `arc4random_uniform(2)`. – jtbandes Dec 17 '15 at 09:24
Ok. But how do I use arc4random?Any idea? – ojassethi Dec 17 '15 at 09:26
Your code works for me with Xcode 7.2 (7C68). – jtbandes Dec 17 '15 at 09:31

How to generate random numbers in Swift 2 Xcode 7?

1 Answers1