Bracket not expected in else statement?

Question

I have an error, unexpected brackets on an else statement, which makes no sense. What am I doing wrong?

if ($sortBy == "random") {
$sortByOption1 = "selected";
} 
else if ($sortBy == "mostvotes") {
$sortByOption2 = "selected";
} 
else ($sortBy == "newest") {
$sortByOption3 = "selected";
}

Error:

syntax error, unexpected '{' on line 9

Also to give an explanation why PHP complains about the `{` and not `(` is because there is no statement between the `else` and `{`. Theoretically you could have done something like this: `else $sortBy = "newest"; {...` — Rizier123, Dec 16 '15 at 19:47

DiddleDot · Accepted Answer · 2015-12-16T19:52:16.483

1

Change the last part of your statement to this

else {
    $sortByOption3 = "selected";
}

Or if you don't want a default value set then change your 'else' to an 'else if'

elseif($sortBy == "newest") {
    $sortByOption3 = "selected";
}

edited Dec 16 '15 at 19:52

answered Dec 16 '15 at 19:46

DiddleDot

745
5
16

score 0 · Answer 2 · answered Dec 16 '15 at 19:50

0

Either change else ($sortBy == "newest") to else if ($sortBy == "newest") or just else. If you are putting a condition it has to be an else if not a plain else.

answered Dec 16 '15 at 19:50

developerwjk

8,619
2
17
33

Bracket not expected in else statement?

2 Answers2