echoing variable works, but not putting inside a file?

Question

I have a variable called $filter. If I run echo $filter; I get the contents of it. However, If I run

file_put_contents("/nrj/vvr/tmp/lol", $filter);

I do get the file, but the contents is just 1. It should contain alot of different things. I use the exact same syntax usually, and it works. I get no error messages.

not getting error messages.. ok. Well, is your system setup "to" catch/log/display? — Funk Forty Niner, Dec 11 '15 at 17:10
and a path like this `"/nrj/vvr/tmp/lol"` implies in wanting to use a system path `"/var/usr/public/nrj/vvr/tmp/lol"` and with a trailing slash perhaps after `lol` - `"/var/usr/public/nrj/vvr/tmp/lol/"` — Funk Forty Niner, Dec 11 '15 at 17:12
@Fred-ii- yes, I get messages about some function in a file I don't use anymore being outdated, just no messages related to that. — DisplayName, Dec 11 '15 at 17:12
@Fred-ii- I have tried it with different paths, the output is still `1` :/. — DisplayName, Dec 11 '15 at 17:14
we need to see what `$filter` is assigned as/coming from. probably a boolean somewhere rather than the intended string, if it's a string. — Funk Forty Niner, Dec 11 '15 at 17:14
well, at this point and not seeing any "answers" below, I think it'll be a while till you do see one. I am moving on, good luck *sincerely*. — Funk Forty Niner, Dec 11 '15 at 17:24
@chris85 I tried that, and it did say it's value was `1`, but that's very strange since I echo it literally the line above and I get my desired value. — DisplayName, Dec 11 '15 at 17:57
That isn't a comparison; that sets/overrides the value. That's the only reason I would see this being 1 (or one of the only reasons). Show more code, such as where you output it or where you set it. — chris85, Dec 11 '15 at 18:02

score 0 · Accepted Answer · answered Dec 11 '15 at 18:25

0

This line was the problem

$filter = curl_exec($ch);

For some reason, it ignores the first things and just executes it without setting any variable. Under this I had

echo $filter;

Giving me the impression that it was that line that output it, but it was the one above.

answered Dec 11 '15 at 18:25

DisplayName

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So this is resolved or you need to get the CURL response to the variable? http://stackoverflow.com/questions/18203411/save-curl-display-output-string-in-variable-php – chris85 Dec 11 '15 at 18:32
@chris85 I have solved the issue in another way, but I had this already set in my code `curl_setopt($url, CURLOPT_RETURNTRANSFER, true);`. – DisplayName Dec 11 '15 at 18:33

echoing variable works, but not putting inside a file?

1 Answers1