While I'm doing typecast from float to int type and typecast from Integer to int it is working. But while i am trying to typecast from Float to int type I'm getting the error as "incompatible type". Why can't we typecast from wrapper to primitive type (Except for its own primitive type).
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Sebastian Brosch
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Ram Thota
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1Why the c++ tag. It is very different to java – Jens Dec 11 '15 at 11:36
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3Possible duplicate of [Cast Double to Integer in Java](http://stackoverflow.com/questions/9102318/cast-double-to-integer-in-java) – Ivaylo Toskov Dec 11 '15 at 11:39
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Becuase, Float is a class type. It derives from Object. But int is a primitive type. You can use floatValue() for conversion.
Q Q
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Yes, thats fine.. Please chech the below code.... Integer i = 10; Float f = (float)i; --->(1) and Float f1 = (Float)i; ---->(2).... Here statement (1) is working but not (2)... why...? – Ram Thota Dec 28 '15 at 10:20
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Well that's kind of what makes the difference between wrapper classes and primitives. It wrapps the value around a Class with useful methods. That's why for converting to int, you'd have to either use
Float f;
int i = (int)(f.floatValue());
or of course
Float f;
int i = f.intValue();
In the sense that a wrapper is a class that wrapps around a certain value, it's more logical to extract a value from that class rather than converting a class to a value.
Note the source code for java.lang.Float: http://grepcode.com/file/repository.grepcode.com/java/root/jdk/openjdk/6-b14/java/lang/Float.java#Float.intValue%28%29 Maybe that makes things clearer.
Luk
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