how can I get the correct decimal for the extended ascii based on windows-1252? Found few symbol will return as unicode instead of ascii number such as below:
symbol: ’ expected: 146 return: 8217
symbol: ” expected: 148 return: 8221
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Roddy of the Frozen Peas
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ctlee
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2Please provide more information on what you are doing, how do you get that character? – Mark Rotteveel Nov 23 '15 at 15:25
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The problem is likely not that you are getting the wrong character value, but that you are analyzing the wrong character. – John Bollinger Nov 23 '15 at 15:29
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this character is from fix which I having issue to generate the correct checksum with counter party – ctlee Nov 23 '15 at 16:48
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’ (8217) is a Unicode Character 'RIGHT SINGLE QUOTATION MARK' (U+2019).
” (8221) is a Unicode Character 'RIGHT DOUBLE QUOTATION MARK' (U+201D).
It seems that your code is expecting:
’ (146) Unicode Character 'PRIVATE USE TWO' (U+0092).
” (148) Unicode Character 'CANCEL CHARACTER' (U+0094).
Which are actually from the Windows-1252 code page.
So, your code is expecting to read Windows-1252, but is receiving Unicode, and the Windows-1252 to Unicode decoding has already taken place when Java read your original file.
Solution: Since your file is already in Windows-1252, and your code wants that, read the file as bytes, not as text.
Andreas
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