Is this x86 assembly addressing method valid?

Question

Is mov al,31[di] a valid instruction? If it is, what does it do?

I'm having a debate and I can't access a computer right now (my android phone is not a computer). As you can see I'm pretty new at assembly and on Stack Overflow so sorry for any rule breaking :)

Looks like MASM/TASM syntax. It effectively takes the byte at memory address _31+value in di register_ and moves it to the 8 bit register `al` — Michael Petch, Nov 20 '15 at 10:06
@Gigel, Oh, so then you _do_ have a computer. One which also makes phone-calls... — enhzflep, Nov 20 '15 at 10:07
@enhzflep : I couldn't resist a bit of an edit to the question. My sense of humour sucks at 3am — Michael Petch, Nov 20 '15 at 10:09

score 4 · Accepted Answer · answered Nov 20 '15 at 09:54

4

Yes, mov al, 31[di] is valid x86 assembly in Intel syntax. It is equivalent to mov al, byte ptr[di + 31].

answered Nov 20 '15 at 09:54

ElderBug

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Is this x86 assembly addressing method valid?

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