Inverse discrete Fourier transform of across specified dimension in Python/Numpy

Question

In Matlab, ifft(X,[],2) (link to documentation) computes the inverse discrete Fourier transform of X across the dimension 2.

Is there a way to accomplish this with numpy.fft.ifft (link to documentation)?

score 1 · Accepted Answer · answered Nov 19 '15 at 23:04

1

Presumably you want

np.fft.ifft(x, axis=1)

In numpy, dimensions are commonly referred to as "axes", and the second dimension is axis 1 (since Python indexing starts at 0 rather than 1).

answered Nov 19 '15 at 23:04

ali_m

Thanks, that's it! I couldn't figure out what the docs meant by axis. – bfletch Nov 20 '15 at 00:57

1 Answers1