Character matching

Question

I need to match a string to have words and not numbers, I need to match special characters such as $!:{}_ if they are part of the word but ignore otherwise.

I have a regex that matches for word and ignores numbers but cannot work out how to match special characters if they are part of the word but ignore otherwise.

Here is what I have correctly - /^d\s+/

Any help would be appreciated.

http://stackoverflow.com/questions/13946651/matching-special-characters-and-letters-in-regex — Mike Sav, Nov 18 '15 at 09:24
what do you mean by `match special characters if they are part of the word but ignore otherwise.` — M.kazem Akhgary, Nov 18 '15 at 09:26
If you use any online regex tester, you will see that [`^d\s+`](https://regex101.com/r/dN8iM5/1) makes very little sense given your requirements. — Wiktor Stribiżew, Nov 18 '15 at 09:30
Example string: This is a test of 1,2,3 word-count - test. So in this example I would expect it to match: This is a test of word-count test it should ignore 1,2,3 and the - that is on its own as it is not part of a word. — user2025749, Nov 18 '15 at 09:34
I have now been given a proper brief: Allow words and letters only, and ignore any numbers. Special characters such as (-_‘[]{}“£$&%!:;\/) should either be ignored or treated as part of the word they sit within. — user2025749, Nov 18 '15 at 09:59

guest271314 · Answer 1 · 2015-11-20T16:42:26.750

Allow words and letters only, and ignore any numbers. Special characters such as (-_‘[]{}“£$&%!:;/) should either be ignored or treated as part of the word they sit within.

Try using String.prototype.replace() with RegExp /\s\d+.*\d|\s+[^a-z]/ig to replace space character followed by digit followed by any character followed by digit , or space character followed by any character not a-z case insensitive

var str = "This is a test of 1,2,3 word-count - test.";

str = str.replace(/\s\d+.*\d|\s+[^a-z]/ig, "");

document.body.textContent = str;

Character matching

1 Answers1