Getting parts of a URL in PHP

Question

How can I extract the following parts using PHP function:

• The Domain
• The path without the file
• The file
• The file with Extension
• The file without Extension
• The scheme
• The port
• The query
• The fragment
• (add any other that you think would be useful)

Ex.1 https://stackoverflow.com/users/test/login.php?q=san&u=post#top

• The Domain (stackoverflow.com)
• The path without the file (/users/test/)
• The file(login.php)
• The file Extension (.php)
• The file without Extension (login)
• The scheme(https:)
• The port(return empty string)
• The query(q=san&u=post)
• The fragment(top)

Ex: 2 stackoverflow.com/users/test/login.php?q=san&u=post#top

• The Domain (stackoverflow.com)
• The path without the file (/users/test/)
• The file(login.php)
• The file Extension (.php)
• The file without Extension (login)
• The scheme(return empty string)
• The port(return empty string)
• The query(q=san&u=post)
• The fragment(top)

Ex: 3 /users/test/login.php?q=san&u=post#top

• The path without the file (/users/test/)
• The file(login.php)
• The file Extension (.php)
• The file without Extension (login)
• The query(q=san&u=post)
• The fragment(top)
• For remaining (return empty string)

Ex: 4 /users/test/login?q=san&u=post#top

• The path without the file (/users/test/)
• The file(login)
• The file Extension (return empty string)
• The file without Extension (login)
• The query(q=san&u=post)
• The fragment(top)
• For remaining (return empty string)

Ex: 5 login?q=san&u=post#top

• The file(login)
• The file Extension (return empty string)
• The file without Extension (login)
• The query(q=san&u=post)
• The fragment(top)
• For remaining (return empty string)

Ex: 6 ?q=san&u=post

• The query(q=san&u=post)
• For remaining (return empty string)

I checked parse_url function, but doesn't return what I need. Since, I'm beginner in PHP, it was difficult for me. If you have any idea, please answer.

Thanks in advance.

Answer 1

PHP provides a parse_url function.

This function parses a URL and returns an associative array containing any of the various components of the URL that are present.

This function is not meant to validate the given URL, it only breaks it up into the above listed parts. Partial URLs are also accepted, parse_url() tries its best to parse them correctly.

---

You can see the test cases executed here.

$urls = array(
  "https://stackoverflow.com/users/test/login.php?q=san&u=post#top",
  "/users/test/login.php?q=san&u=post#top",
  "?q=san&u=post#top",
  "login.php?q=san&u=post#top",
  "/users/test/login?q=san&u=post#top",
  "login?q=san&u=post#top"
);
foreach( $urls as $x ) {
  echo $x . "\n";
  var_dump( parse_url($x) );
}

Answer 2

I"m using this to locate the root and webroot

<?php

/**
 * @brief get paths from the location where it was executed.
 */
class PathHelper {
    /**
     * @brief This function tries to determine the FileSystem root of the application. (needs to be executed in the root)
     * @return string
     */
    public static function locateRoot($file) {
        $dir = dirname($file);
        /** FIX Required for WINDOWS * */
        $dir = preg_replace('/\\\\/', '/', $dir);
        $dir = preg_replace('/\\\/', '/', $dir);
        return $dir;
    }

    /**
     * @brief This function tries to determine the WebRoot. (needs to be executed in the root)
     * @return string
     */
    public static function locateWebroot($file) {
        $docroot = $_SERVER['DOCUMENT_ROOT'];
        $dir = dirname($file);
        if ($dir == $docroot) {
            $webroot = "";
        } else {
            $webroot = substr_replace($dir, '', 0, strlen($docroot));
        }
        /** FIX Required for WINDOWS * */
        $webroot = preg_replace('/\\\\/', '/', $webroot);
        $webroot = preg_replace('/\\\/', '/', $webroot);
        return $webroot;
    }
}

I set this as a constant so i can use it throughout my application.

For example:

For a menu you can do something like this:

   // the requested url
    $requestedUrl = $_SERVER['REQUEST_URI'];

    // remove the webroot from the requested url
    $requestedUrl = str_replace(WEBROOT, "", $_SERVER['REQUEST_URI']);

    // take away the / if they still exist at the beginning
    $requestedUrl = ltrim($requestedUrl, "/");

Then i got this: index.php?controller=User&action=overview

This equals to my url of one of my menu items. You could use explode on this last url to find all the other values you want.

Edit: Its probably better to use parse_url(). I am not used to all the functions in PHP but if nothing works then this is atleast a fallback.