Function Javascript return

Question

Can you check if I return a function correct:

JS
$(eachsection).each(function() {
   listfunction();
}


function listfunction(){
  $(this).show();
  $(this).find('a.q_weblinksprite_med').attr("onclick", construct_url);
  $(this).find('.q_weblinksprite_med').text(itemTitle);
  $(this).find(".status").text(itemStatus);
  $(this).find('.q_rt_rowcell-1-title').text(itemCategory);
  $(this).find('.q_clipline').html(itemContent);
}

What I want is just to return all content from listfunction(). Thanks!

Right now you're not returning anything in any function..what is it exactly that you need? — cviejo, Nov 11 '15 at 15:24
from this snippet I see that you haven't closed each method, then try to write this way `$(eachsection).each(listfunction); function listfunction(){ ... return $(this); }` — Danil Gudz, Nov 11 '15 at 15:51
well just print or debug what your method returns and you'll know if its correct... that's how i see it... — mikus, Nov 11 '15 at 16:11
Possible duplicate of [Remove .php extension with PHP](http://stackoverflow.com/questions/1337695/remove-php-extension-with-php) — mikus, Nov 11 '15 at 16:13

Alan Rezende · Accepted Answer · 2015-11-11T16:07:40.200

1

The code you posted isn`t returning anything.

By the look, you could return a array

function listfunction(){
  var myReturn = {};
  $(this).show();
  myReturn['url'] = $(this).find('a.q_weblinksprite_med').attr("onclick", construct_url);
  myReturn['title'] = $(this).find('.q_weblinksprite_med').text(itemTitle);
  myReturn['status'] = $(this).find(".status").text(itemStatus);
  myReturn['category'] = $(this).find('.q_rt_rowcell-1-title').text(itemCategory);
  myReturn['content'] = $(this).find('.q_clipline').html(itemContent);
  return myReturn;
}

Is this what you are looking for?

edited Nov 11 '15 at 16:07

answered Nov 11 '15 at 15:28

Alan Rezende

348
2
11

fix `var myReturn;` furthermore you have to init this value as an object `var myReturn = {};` – Danil Gudz Nov 11 '15 at 15:51
Thanks @GudzDaniel, fixed. – Alan Rezende Nov 11 '15 at 16:08

score 0 · Answer 2 · edited Nov 11 '15 at 15:48

Calling listfunction() from where you have it will cause you to lose scope. So if you are attempting to call $(this).show() and have it show the element you looped through, you would need to call it like this:

$(eachsection).each(function() {
   listfunction(this);
}


function listfunction(element){
  $(element).show();
  $(element).find('a.q_weblinksprite_med').attr("onclick", construct_url);
  $(element).find('.q_weblinksprite_med').text(itemTitle);
  $(element).find(".status").text(itemStatus);
  $(element).find('.q_rt_rowcell-1-title').text(itemCategory);
  $(element).find('.q_clipline').html(itemContent);
}

Function Javascript return

2 Answers2