preg_grep with html source

Question

I want extract this line

<p>@include{"portal.shared.blook"}</p>

using

preg_grep("/(\s*@include.*)/",explode("\n", $Source))

from this source code

<html>
   <head>
        <title>hi</title>
   </head>
   <body>
        <h1>Hi I am layout</h1>
        <br>
        <p>@include{"portal.shared.blook"}</p>
        @require{"portal.shared.footer":"[main]"}

Some times the code has whitespace and I can not handle it

Will this line be same always like this? `
@include{"Some Text here"}
` — Thamilhan, Nov 11 '15 at 07:03
i reach this preg_grep('/(@include{"(.*)"}*)/',explode("\n", $Source) but still show me the
tag — A.H, Nov 11 '15 at 07:06
You could do something like this afterwards: `preg_replace('/
/', '', preg_replace('/
/', '', $string));` — Mads Marquart, Nov 11 '15 at 07:08

William J. · Answer 1 · 2015-11-11T07:12:10.233

1

Try this:

(?<=\<\w\>)(\s*@include.*)(?=\<\/\w\>)

Working example: https://regex101.com/r/wM1lB8/2

edited Nov 11 '15 at 07:12

answered Nov 11 '15 at 07:10

William J.

1,574
15
26

I reach this "(@include{"(.*)"}*)" its oky on online tester but locally in php still has
attached
– A.H Nov 11 '15 at 07:22
How are you using it in the PHP code? can you post it? – William J. Nov 11 '15 at 07:24
sure , $Source is html file foreach(preg_match('/(@include{"(.*)"}*)/', $Source) as $Tempstring) { print_r( $Tempstring); } – A.H Nov 11 '15 at 07:28
preg_match returns an int. You shouldn't use this way. You can do something like: `preg_match('/(?<=\<\w\>)(\s*@include.*)(?=\<\/\w\>)/', $Source, $matches);` then iterate over `$matches` – William J. Nov 11 '15 at 07:35

preg_grep with html source

1 Answers1