How to check enum case of enum with associated values in Swift

Question

I'm trying to check the case of an enum that has associated values for each case like this:

enum status {
    case awake(obj1)
    case sleeping(obj2)
    case walking(obj3)
    case running(obj4)
}

I'm using if(status == deviceStatus.awake){ to check status case and am getting an error: Binary operator '==' cannot be applied to operands of type 'status' and '(obj1) -> status'

Where have you defined your deviceStatus? and what type of those objects (obj1, obj2, ...) are? — Shoaib, Nov 03 '15 at 01:50
Possible duplicate of http://stackoverflow.com/q/31548855/994104 — Jeremy, Jun 21 '16 at 20:44

vacawama · Accepted Answer · 2019-01-28T11:28:09.683

You can use if case .awake = deviceStatus to check if deviceStatus is set to the awake enumeration value:

class Obj1 { }
class Obj2 { }
class Obj3 { }
class Obj4 { }

enum Status {
    case awake(Obj1)
    case sleeping(Obj2)
    case walking(Obj3)
    case running(Obj4)
}

let deviceStatus = Status.awake(Obj1())

if case .awake = deviceStatus {
    print("awake")
} else if case .sleeping = deviceStatus {
    print("sleeping")
}

// you can also use a switch statement

switch deviceStatus {
case .awake:
    print("awake")
case .sleeping:
    print("sleeping")
default:
    print("something else")
}

How to check enum case of enum with associated values in Swift

1 Answers1