PHP - array_unique not changing output

Question

I have an array $tmp:

$a = array(0 => 49, 1 => 49, 2 => 49);

after using array_unique($tmp) I'm getting this output:

Array
(
    [0] => 49
    [1] => 49
    [2] => 49
)

and I want to get

Array
(
    [0] => 49
)

What am I doing wrong? Im new in PHP

Obviously you show us not real code, or values in array are somehow different. Maybe with spaces or some hidden symbols around. Do a `var_dump($tmp);` — u_mulder, Oct 31 '15 at 14:40

Hanky Panky · Answer 1 · 2015-10-31T17:23:06.380

You don't only need to call that function you need to use the returned value as well. Do

$tmp=array_unique($tmp);

Just calling that function and not picking up the returned value does no good.

There are some functions that operate on the original variable and hence you dont need to pick up their ret val for example sort() but array_unique() is not one of them. Always refer to http://www.php.net/functionName to find out

score 3 · Accepted Answer · edited Oct 31 '15 at 14:45

3

$input = array(49,49,49);

$result = array_unique($input);

print_r($result);

edited Oct 31 '15 at 14:45

Funk Forty Niner

74,450
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answered Oct 31 '15 at 14:44

Virag Shah

64
2

3

Drop-in answer; care to "explain"? for future readers to the question. – Funk Forty Niner Oct 31 '15 at 14:45

PHP - array_unique not changing output

2 Answers2