I think the basic idea is to use Levenshtein distance, but on a subset of the names. One approach that works if the names are long enough is to use n-grams. You can store n-grams and then use more efficient techniques to say that at least x n-grams need to match. Alas, your example misspelling has 2-matching 3-grams with Chicago out of 5 (unless you count partials at the beginning and end).
For shorter names, another approach is to store the letters in each name. So, "Chicago" would turn into 6 "tuples": "c", "h", "i", "a", "g", "o". You would do the same for the name entered and then require that 4 or 5 match. This is a fairly simple match operation, so it can go quite fast.
Then, on this reduced set, apply Levenshtein distance to determine what the closest match is.