NoReverseMatch ... and keyword arguments '{}' not found. 0 pattern(s) tried: []

Question

I'm new to django. I've tried the tutorial so many times. I now have started my own project until I am faced with NoReverseMatch ... and keyword arguments '{}' not found. 0 pattern(s) tried: []

my template section_list.html

{% for section in section_name %}
    <a href='{% url 'employee_listings' hsection section %}' >
       {{ section }}

 </br>
{% endfor %}

urls.py

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^letters/(?P<employee_id>\d+)$', views.letters, name='letters'),    
    url(r'(?P<word>\d+)/$', views.headsection_listings, name='headsection_listings'),
    url(r'(?P<hsection>\w+)$', views.section_listings, name='section_listings'),
    url(r'(?P<hsection>\w+)/(?P<section>\w+)/$', views.employee_listings, name='employee_listings'),
    )

views.py

def employee_listings(request, hsection, section):
    #import pdb; pdb.set_trace()
    employee_list = Employee.objects.all()
    employee_id = [p.emp_id for p in employee_list if p.section.section_name == section]
    employee_name = [p.emp_first_name +' ' +  p.emp_last_name for p in employee_list if p.section.section_name == section]
    #    import pdb; pdb.set_trace()
    context = {'employee_name':employee_name, 'section':section, 'employee_id':employee_id}
    return render(request, 'kapra/employee_list.html', context)

def section_listings(request, hsection):
    section_list = Section.objects.all()
#    import pdb; pdb.set_trace()
    section_name = [p.section_name for p in section_list if p.headsection.head_section_name == hsection]
    context = {'section_name':section_name, 'hsection':hsection}
    return render(request, 'kapra/section_list.html', context)

Browser Output: NoReverseMatch at /kapra/Administration

Reverse for 'section_listings' with arguments '(u'Administration', u'Employee Admin')' and keyword arguments '{}' not found. 0 pattern(s) tried: []
.... Reverse for 'section_listings' with arguments '(u'Administration', u'Employee Admin')' and keyword arguments '{}' not found. 0 pattern(s) tried:[]

django_version 1.6.11 if I don't use {% url %} and use {/kapra/...} format it works.

Sorry, I posted irrevalent view at first, its edited now. The view section_listings is not being matched actually. — sandish, Oct 31 '15 at 08:55
You are trying to solve an url that does not exist. maybe try {% url 'employee_listings' hsection section %} — cdvv7788, Oct 31 '15 at 08:58
Or update your url for section_listing to receive 2 keywords, not 1. — cdvv7788, Oct 31 '15 at 08:59
I'm sorry for the error. I actually tried {% url 'employee_listings' hsection section %} the error is Reverse for 'employee_listings' with arguments '(u'Administration', u'Employee Admin')' and keyword arguments '{}' not found. 0 pattern(s) tried: [] — sandish, Oct 31 '15 at 09:06
Do you really mean to be passing `(u'Administration', u'Employee Admin')` to `{% url %}`? Is the space intended? You expect the URL to be `/Administration/Employee Admin/`? — Mike Covington, Oct 31 '15 at 09:13
yes, indeed. the NoReverseMatch error comes in every other views as well, the other format though works everywhere. I've tried the namespace, 'kapra:employee_listings' as namespace in project urls.py is 'kapra'. Its the problem with matching reverse — sandish, Oct 31 '15 at 09:16

score 0 · Answer 1 · answered Oct 31 '15 at 09:04

0

You are passing two arguments besides the URL name to {% url ... %}:

{% url 'section_listings' hsection section %}

However, both your urls.py and views.py suggest you should only pass one extra argument:

# urls.py
url(r'(?P<hsection>\w+)$', views.section_listings, name='section_listings'),
# views.py:
def section_listings(request, section):

Try this instead in your template:

{% url 'section_listings' hsection %}

or, since you have a named argument in your url, you can use:

{% url 'section_listings' hsection=hsection %}

answered Oct 31 '15 at 09:04

Mike Covington

2,147
1
16
26

{% for hsection in head_section_name %} {{ hsection }} {% endfor %} ... this works but {{ section }} does not. – sandish Oct 31 '15 at 09:10
I'm confused now. You just changed your question to say it is a different problem. So is section_listing working or not? – Mike Covington Oct 31 '15 at 09:12
I'm in fedora 21, the , .... , url(r'(?P\w+)/(?P
\w+)/$', views.employee_listings, name='employee_listings'),....., def employee_listings(request, hsection, section): ... have not been working.
– sandish Oct 31 '15 at 09:21
Did you try this: `{% url 'section_listings' hsection=hsection %}` or `{% url 'employee_listings' hsection=hsection section=section %}`? – Mike Covington Oct 31 '15 at 09:22
Are you sure that `section` and `hsection` are what you expect they are? What about passing actual strings that you know for certain should work? – Mike Covington Oct 31 '15 at 09:27
How do I pass actual string? (u'Administration', u'Employee Admin') where they are hsection=Administration section=Employee Admin – sandish Oct 31 '15 at 09:37
Actually, other views are not working too in this regard. – sandish Oct 31 '15 at 09:39
Well, your regex is `r'(?P\w+)/(?P
\w+)/$'` and you are using `'Employee Admin'` for section. There is no way for that to match `\w+`, since `\w+` means 1 or more 'word' characters such as `[A-Za-z0-9_]`. You have a space and `\w` won't match a space.
– Mike Covington Oct 31 '15 at 09:41
What do I do to include space? Please improve my regex for space inclusion. – sandish Oct 31 '15 at 09:46
Well, `[\w\s]+` would let you have a space, but you really shouldn't be using URLs with spaces. Maybe you want to be using a slug field instead https://docs.djangoproject.com/en/1.8/ref/models/fields/#slugfield – Mike Covington Oct 31 '15 at 09:48

Sebastian Wozny · Answer 2 · 2015-10-31T09:51:03.313

0

You are missing one slash at the end of the URL you are calling:

/kapra/Administration

should be

/kapra/Administration/

Consider manipulating your pattern to allow to omit the slash:

url(r'(?P<hsection>\w+)/(?P<section>\w+)/?$', views.employee_listings, name='employee_listings'),

Note the ? after the last slash According to the documentation for url,you are passing args when you should pass kwargs. Try passing kwargs:

{% for section in section_name %}
    <a href='{% url 'employee_listings' hsection=hsection section=section %}' >
       {{ section }}
     </br>
{% endfor %}

Explanation:

You may pass args to a pattern like this:

url(r'^client/([0-9]+)/$', app_views.client, name='app-views-client')

But only kwargs to this:

 url(r'(?P<hsection>\w+)/(?P<section>\w+)/$', views.employee_listings, name='employee_listings'),

You cannot mix kwargs and args in one {% 'url' %} call.

edited Oct 31 '15 at 09:51

answered Oct 31 '15 at 09:18

Sebastian Wozny

16,943
7
52
69

Reverse for 'employee_listings' with arguments '()' and keyword arguments '{u'section': u'Employee Admin', u'hsection': u'Administration'}' not found. 0 pattern(s) tried: [] didn't work either. – sandish Oct 31 '15 at 09:23
Are you sure? I interpreted that as not being able to mix it like this: `{% url 'employee_listings' hsection=hsection section %}`. Because in 1.8, I pass an argument to a url that is defined w/ named variables and it works just fine. – Mike Covington Oct 31 '15 at 09:25
I'm sure, I did not mix it. I'm in Django 1.6.11 – sandish Oct 31 '15 at 09:42

NoReverseMatch ... and keyword arguments '{}' not found. 0 pattern(s) tried: []

2 Answers2