How to create particular month and/or date sequence "n" number of times

Question

I am trying to create a sequence of months from Jan- Dec 3 times. ie. Jan Feb Mar . . . . Dec Jan Feb Mar . . . . Dec Jan Feb Mar . . . . Dec

I tried this code

rep(c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec"),each=3)

but it generates result like this

[1] "Jan"  "Jan"  "Jan"  "Feb"  "Feb"  "Feb"  "Mar"  "Mar"  "Mar"  "Apr"  "Apr"  "Apr" 
[13] "May"  "May"  "May"  "Jun"  "Jun"  "Jun"  "Jul"  "Jul"  "Jul"  "Aug"  "Aug"  "Aug" 
[25] "Sept" "Sept" "Sept" "Oct"  "Oct"  "Oct"  "Nov"  "Nov"  "Nov"  "Dec"  "Dec"  "Dec"

but I want Jan Feb Mar....Dec Jan Feb Mar.....Dec Jan Feb Mar...Dec

Thanks Harshad

try `rep(c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec"),3)` — jeremycg, Oct 30 '15 at 12:16
use `times=` in rep. Also you can make it compact `rep(month.abb, 3)` — akrun, Oct 30 '15 at 12:16

score 9 · Answer 1 · answered Oct 30 '15 at 12:21

9

We can use month.abb instead of c('Jan', 'Feb'), etc..

 rep(month.abb, 3)

For full month name

 rep(month.name, 3)

answered Oct 30 '15 at 12:21

akrun

874,273
37
540
662

1

Good to see the use of internal vectors. – Pierre L Oct 30 '15 at 12:25
1

Thanks...yeah neat and clean way it is. – Harshad M Oct 30 '15 at 13:13

score 2 · Answer 2 · answered Oct 30 '15 at 12:16

Use times=3

rep(c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec"),times=3)
#  [1] "Jan"  "Feb"  "Mar"  "Apr"  "May"  "Jun"  "Jul"  "Aug"  "Sept" "Oct"  "Nov"  "Dec"  "Jan" 
# [14] "Feb"  "Mar"  "Apr"  "May"  "Jun"  "Jul"  "Aug"  "Sept" "Oct"  "Nov"  "Dec"  "Jan"  "Feb" 
# [27] "Mar"  "Apr"  "May"  "Jun"  "Jul"  "Aug"  "Sept" "Oct"  "Nov"  "Dec"

How to create particular month and/or date sequence "n" number of times

2 Answers2