What is the lldb equivalent of gdb's --args?

Question

I'm used to running gdb like so:

$ gdb --args exe --lots --of --flags -a -b -c d e
...
(gdb) r

Is there an equivalent for lldb?

score 37 · Accepted Answer · answered Oct 29 '15 at 21:08

37

Yes, it's just -- instead of --args. From the help:

lldb -v [[--] <PROGRAM-ARG-1> [<PROGRAM_ARG-2> ...]]

Thus:

$ lldb -- exe --lots --of --flags -a -b -c d e

answered Oct 29 '15 at 21:08

Claudiu

Note that if you came here searching for "how to make lldb run my program immediately", you will want to use `lldb -o run -- exe --flags`. Also see [this question](https://reverseengineering.stackexchange.com/questions/10586/how-to-run-automatically-executable-from-cli-using-lldb) – cfstras Jun 14 '23 at 15:32

score 7 · Answer 2 · answered Aug 02 '17 at 09:59

7

You can also start lldb first and use:

(lldb) settings set target.run-args 1 2 3
(lldb) run

or:

(lldb) process launch -- <args>

answered Aug 02 '17 at 09:59

Patryk Gawroński

That was helpful! – ruoho ruotsi Jun 07 '19 at 20:13
If you want to add option arguments starting with '-' you can use: `settings set -- target.run-args "-d"` – Seunghoon Nov 02 '22 at 01:03

score 0 · Answer 3 · answered Jul 02 '23 at 08:28

0

just run 'run arg1 arg2' in lldb

answered Jul 02 '23 at 08:28

Princekin

3 Answers3