Hibernate: @Formula query field using another @Formula field

Question

I want field idEmpresa to be a @Formula field using idDepartamento (that is another @Formula field) in WHERE statement.

@Entity
public class CfgUsuario {

    //More fields
    private String idDepartamento;
    private String idEmpresa;


    @Formula("(SELECT ud.IdDepartamento FROM UsuarioDpto ud WHERE ud.PorDefecto = 'S' AND ud.IdUsuario = idUsuario)")
    public String getIdDepartamento() {
        return idDepartamento;
    }

    public void setIdDepartamento(String idDepartamento) {
        this.idDepartamento = idDepartamento;
    }

    @Formula("(SELECT d.IdEmpresa FROM Departamento d WHERE d.IdDepartamento = idDepartamento)")
    public String getIdEmpresa() {
        return idEmpresa;
    }

    public void setIdEmpresa(String idEmpresa) {
        this.idEmpresa = idEmpresa;
    }

}

But I get:

javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: Column name 'idDepartamento' invalid.

score 9 · Accepted Answer · answered Oct 27 '15 at 12:33

It seems that you are trying to create a valid HQL / JPQL statement, but if you read the JavaDoc of Formula you will see:

The formula has to be a valid SQL fragment

So you can't reference any field from your class, only tables and columns from your database.

But you can change your Formula to use a JOIN instead:

@Formula("(SELECT ud.IdDepartamento FROM UsuarioDpto ud WHERE ud.PorDefecto = 'S' AND ud.IdUsuario = idUsuario)")
public String getIdDepartamento() {
    return idDepartamento;
}

@Formula("(SELECT d.IdEmpresa FROM Departamento d JOIN UsuarioDpto ud ON d.IdDepartamento = uid.idDepartamento WHERE ud.PorDefecto = 'S' AND ud.IdUsuario = idUsuario)")
public String getIdEmpresa() {
    return idEmpresa;
}

And I would remove the setters of your formulas, as they will confuse any user of your API. Formula fields are usually read-only.

Hibernate: @Formula query field using another @Formula field

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