Make an app impossible to quit

Question

I want to make an app I have impossible to quit by normal means, only by forcequitting. Is this possible? (I do have limited knowledge of bash)

I use MacOSX ElCapitan. Thank you in advance for the help!

Edit: To clarify, I want it not to be able to quit with ⌘+Q or by rightclicking the app and pressing quit, or quitting through the App menu on the top bar.

score -1 · Answer 1 · answered Oct 26 '15 at 00:48

-1

You could intercept any control-c type signals with a signal handler. Here is an example:

#!/bin/bash
trap "echo 'Caught Signal'" SIGHUP SIGINT SIGTERM
while true; do
    echo "looping"
    sleep 5
done

answered Oct 26 '15 at 00:48

John C

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Sorry, but I don't understand how to do a signal handler. How can I factor in the app itself? – AAM111 Oct 26 '15 at 20:31
This is only relevant to a shell script, not a general OS X app. – chepner Oct 26 '15 at 20:39
Its tagged as a bash problem. So I answered it as a bash problem. – John C Oct 27 '15 at 06:01

Make an app impossible to quit

1 Answers1