Calculating a month in julian counting (year starts with march) with basic arithmetic only

Question

I am trying to convert an integer representing a month (1=january, 2=february.. 12=december) to an integer representing that month but in julian counting (1=march, 2=april.. 12=february). However I can only use integers and basic arithmetic (-,+,/,* and modulo).

for example:

month->julianMonth  
1->11  
2->12   
3->1   
4->2   
5->3  
...

The closest I get is with

julianMonth=(month+10)%12

which returns every value right but february.

`%12` will return the sequence `0,1,...,11,0,1,...` so throw in a `+1` at the right place in your calculation. — High Performance Mark, Oct 25 '15 at 13:44
... probably rewrite the *rhs* to `(month+9)%12+1` (untested) — High Performance Mark, Oct 25 '15 at 13:52

score 0 · Answer 1 · answered Oct 25 '15 at 14:02

0

Okay, got it:

julianMonth=(month+9)%12+1

answered Oct 25 '15 at 14:02

octavio

456
4
14

It would be polite to reference High Performance Mark, if that's where you got the answer. – Teepeemm Oct 26 '15 at 05:20

Calculating a month in julian counting (year starts with march) with basic arithmetic only

1 Answers1