int val = -10;
cout << ++(-val) << endl;
Output should be 11. But it gives me an error.
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M. Blue
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`-val` isn't a lvalue. – πάντα ῥεῖ Oct 25 '15 at 09:53
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-val will make it 10 – M. Blue Oct 25 '15 at 09:54
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--val will make it 10 – rakagunarto Oct 25 '15 at 09:55
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2Can you increment a literal like `10++;`? It's the same effect. – πάντα ῥεῖ Oct 25 '15 at 09:55
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What would be the use case? You *can* write `val = -val + 1`. – Bo Persson Oct 25 '15 at 11:41
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The error is "lvalue required as increment operand". This means that it's just a value; it does not represent a particular object like "val" anymore so trying to change it makes no sense to the compiler.
fatihk
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