Node app, perfectly valid JSON, how is "d" not defined?

Question

I'm trying to run the EasyRTC default server code and examples.

If you look at the Node console you can see the JSON string returned in "body". Then immediately after, I get an error that "d" is not defined. The JSON is valid so how can this be?

Thanks for taking a look. I really need your advice.

score 2 · Answer 1 · answered Oct 21 '15 at 12:51

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So as per usual, about 5 minutes after posting here, the answer comes to me...

body = JSON.parse(body)

answered Oct 21 '15 at 12:51

Locohost

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To be clear to anyone reading, the `body` is a string when passed through the argument so you need to parse it as a valid JSON object. – Jacob Morrison Oct 21 '15 at 13:27
Just so. Thanks Jake :-) – Locohost Oct 22 '15 at 13:15

score 0 · Answer 2 · answered Oct 21 '15 at 12:56

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console.log("typeof body=", typeof body);

Returns "object" or "string" ? It must be a string so you must JSON.parse it first.

answered Oct 21 '15 at 12:56

Ilya Kharlamov

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Node app, perfectly valid JSON, how is "d" not defined?

2 Answers2