Time Division Multiplexing: Frame rate and bit rate

Question

Can someone explain to me how to get the answer I am so lost.

Q1. A multiplexer combines four 100-kbps channels using a time slot of 2 bits. What is the frame rate and the bit rate?

The answer is 50,000 Frame per sec and 400 kbps.

4 * 100kbps = ?. 100kbps / 2b = ? – hobbs Oct 18 '15 at 23:06 — hobbs, Oct 18 '15 at 23:06
oh ok i get it, but how do you turn 50,000 fps to 400 kbps? – Mebighobo Oct 18 '15 at 23:14 — Mebighobo, Oct 18 '15 at 23:14

score 1 · Answer 1 · edited Apr 30 '21 at 12:27

1

bit rate = no. of channels * Input bit rate

So, bit rate = 4 * 100kbps = 400kbps

Frame rate = Input bit rate (convert it into bit) / time slot bit(s)

So, Frame rate = 100000bps / 2b = 50000 frames per second (Frames/s)

edited Apr 30 '21 at 12:27

Sallar Rabiei

630
1
12
33

answered Apr 29 '21 at 20:20

Ishraq Ahmed Esha

11
4

score 0 · Accepted Answer · answered Oct 18 '15 at 23:58

0

4 * 100kbps = 400kbps

100kbps / 2b = 100000bps / 2b = 50000fps

answered Oct 18 '15 at 23:58

Milan Rakos

1,705
17
24

score -1 · Answer 3 · edited Dec 17 '20 at 13:34

-1

Frame rate is the number of frames per second. If we have 400000 bits per second transmission Since each frame carries 8 bits, the frame rate would be: 400000/8 = 5000 per second.

edited Dec 17 '20 at 13:34

dboy

1,004
2
16
24

answered Dec 17 '20 at 10:30

user14843288

1

Time Division Multiplexing: Frame rate and bit rate

3 Answers3