winexe can not exit if launched from lua

Asked Oct 16 '15 at 07:47

Active Oct 16 '15 at 08:24

Viewed 79 times

I running my program in lua and the winexe function is launched by lua, the problem is the winexe will start correctly but does not exit. I had used file:flush(),file:close() and os.exit(), they all not working.Blow is my code:

local command = "/root/logoff_script";
 local file = io.popen(command,'r');
 file:write("\n");
 file:flush();
 local output = file:read('*all');
 file:close();

Can you help me? Thanks

edited Oct 16 '15 at 08:24

Egor Skriptunoff

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asked Oct 16 '15 at 07:47

JG.Wang

`popen` can't be used for reading AND writing. Either read or write, [not both](http://lua-users.org/lists/lua-l/2007-10/msg00189.html). – Egor Skriptunoff Oct 16 '15 at 08:07
you mean I should delete the "file:write("\n")" line? I tried, it didn't work – JG.Wang Oct 16 '15 at 08:18
Yes, if you have selected mode "r" in `io.popen(command,'r')` then you can't write and flush. – Egor Skriptunoff Oct 16 '15 at 08:24
Actually, I changed this code as io.popen(command,'w') and it can work now. But I don't understand why it can not exit when I use 'read' – JG.Wang Oct 22 '15 at 08:00
Because winexe waits for some user input prior to exiting? – Egor Skriptunoff Oct 22 '15 at 09:29
so I need add some ? – JG.Wang Oct 22 '15 at 09:37
You can `io.popen("echo Something | ./your_program","r")` to feed something to your program – Egor Skriptunoff Oct 22 '15 at 11:49

winexe can not exit if launched from lua

0 Answers0