Laravel 5.1 custom 404 based on route

Question

I'm new to laravel. I want to display a custom 404 error depending on requested url.

Example:
site.com/somepage
and
site.com/admin/somepage

I've see this answer but it's for laravel 4. I can't find the equivalent answer for Laravel 5.1

Please help. Thanks!

-- ANSWER --

My code based on suggestion by Abdul Basit

//Handle Route Not Found
if ($e instanceof NotFoundHttpException) {
    //Ajax Requests
    if ($request->ajax() || $request->wantsJson()) {
        $data = [
            'error' => true,
            'message' => 'The route is not defined',
        ];
        return Response::json($data, '404');
    } else {
        //Return view
        if (Request::is('admin/*')) {
            return Response::view('admin.errors.404', array(), 404);
        } else {
            return Response::view('errors.404', array(), 404);
        }
    }
}

//Handle HTTP Method Not Allowed
if ($e instanceof MethodNotAllowedHttpException) {
    //Ajax Requests
    if ($request->ajax() || $request->wantsJson()) {
        $data = [
            'error' => true,
            'message' => 'The http method not allowed',
        ];
        return Response::json($data, '404');
    } else {
        //Return view
        if (Request::is('admin/*')) {
            return Response::view('admin.errors.404', array(), 404);
        } else {
            return Response::view('errors.404', array(), 404);
        }
    }
}

did you try with that probably it will suit with the `5.1` also — Kalhan.Toress, Oct 12 '15 at 09:14

score 3 · Accepted Answer · answered Oct 12 '15 at 09:16

You can do the logic for that in render method of App\Exceptions\Handler in app\Exceptions\Handler.php

public function render($request, Exception $e)
{
    //Handle Route Not Found
    if ($e instanceof Symfony\Component\HttpKernel\Exception\NotFoundHttpException)
    {
        //Ajax Requests
        if($request->ajax() || $request->wantsJson())
        {
            $data = [
                'error'   => true,
                'message' => 'The route is not defined',
            ];
            return Response::json($data, '404');
        }
        else
        {
            //Return view 
            return response()->view('404');
        }
    }
    //Handle HTTP Method Not Allowed
    if ($e instanceof Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException)
    {
        //Ajax Requests
        if($request->ajax() || $request->wantsJson())
        {
            $data = [
                'error'   => true,
                'message' => 'The http method not allowed',
            ];
            return Response::json($data, '404');
        }
        else
        {
            //Return view 
            return response()->view('404'); 
        }
    }
    return parent::render($request, $e);
}

score 0 · Answer 2 · answered Oct 02 '16 at 07:27

Laravel makes it easy to display custom error pages for various HTTP status codes. For example, if you wish to customize the error page for 404 HTTP status codes, create a resources/views/errors/404.blade.php. This file will be served on all 404 errors generated by your application. The views within this directory should be named to match the HTTP status code they correspond to.

score 0 · Answer 3 · answered Feb 07 '20 at 07:57

Check the fallback route, you may define a route that will be executed when no other route matches the incoming request, The fallback route should always be the last route registered by your application. https://laravel.com/docs/5.8/routing#fallback-routes

Route::fallback(function () {
    //Send to 404 or whatever here.
});

Laravel 5.1 custom 404 based on route

-- ANSWER --

3 Answers3