SQL group by day, show orders for each day

Question

I have an SQL 2005 table, let's call it Orders, in the format:

OrderID, OrderDate,  OrderAmount
1,       25/11/2008, 10
2,       25/11/2008, 2
3,       30/1002008, 5

Then I need to produce a report table showing the ordered amount on each day in the last 7 days:

Day,        OrderCount, OrderAmount
25/11/2008, 2,          12
26/11/2008, 0,          0 
27/11/2008, 0,          0 
28/11/2008, 0,          0
29/11/2008, 0,          0
30/11/2008, 1,          5

The SQL query that would normally produce this:

select count(*), sum(OrderAmount)
    from Orders
    where OrderDate>getdate()-7
    group by datepart(day,OrderDate)

Has a problem in that it will skip the days where there are no orders:

Day,        OrderCount, OrderAmount
25/11/2008, 2,          12
30/11/2008, 1,          5

Normally I would fix this using a tally table and outer join against rows there, but I'm really looking for a simpler or more efficient solution for this. It seems like such a common requirement for a report query that some elegant solution should be available for this already.

So: 1. Can this result be obtain from a simple query without using tally tables?

and 2. If no, can we create this tally table (reliably) on the fly (I can create a tally table using CTE but recursion stack limits me to 100 rows)?

This link has complete information on grouping data by - day - day of month - day of week - day of year in detail with exaples. http://sqlserverlearner.com/2012/group-by-day-with-examples — , May 02 '12 at 08:15
Related information can be found here: http://stackoverflow.com/questions/95257/how-to-get-a-table-of-dates-between-x-and-y-in-sql-server-2005 — Amy B, Dec 01 '08 at 21:08

score 10 · Answer 1 · answered Nov 30 '08 at 22:31

SQL isn't "skipping" dates... because queries run against data that is actually in the table. So, if you don't have a DATE in the table for January 14th, then why would SQL show you a result :)

What you need to do is make a temp table, and JOIN to it.

CREATE TABLE #MyDates ( TargetDate DATETIME )
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 0, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 1, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 2, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 3, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 4, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 5, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 6, 101))
INSERT INTO #MyDates VALUES CONVERT(DATETIME, CONVERT(VARCHAR, GETDATE() - 7, 101))

SELECT CONVERT(VARCHAR, TargetDate, 101) AS Date, COUNT(*) AS OrderCount
FROM dbo.Orders INNER JOIN #MyDates ON Orders.Date = #MyDates.TargetDate
GROUP BY blah blah blah (you know the rest)

There you go!

score 2 · Answer 2 · answered Oct 26 '10 at 05:37

I had the same problem and this is how I solved it:

SELECT datename(DW,nDays) TimelineDays, 
    Convert(varchar(10), nDays, 101) TimelineDate,
    ISNULL(SUM(Counter),0) Totals 
FROM (Select GETDATE() AS nDays
    union Select GETDATE()-1
    union Select GETDATE()-2
    union Select GETDATE()-3
    union Select GETDATE()-4
    union Select GETDATE()-5
    union Select GETDATE()-6) AS tDays

Left Join (Select * From tHistory Where Account = 1000) AS History
            on (DATEPART(year,nDays) + DATEPART(MONTH,nDays) + DATEPART(day,nDays)) = 
            (DATEPART(year,RecordDate) + DATEPART(MONTH,RecordDate) + DATEPART(day,RecordDate)) 
GROUP BY nDays
ORDER BY nDays DESC

The ouput is:

TimelineDays,   TimelineDate,     Totals

Tuesday         10/26/2010        0
Monday          10/25/2010        6
Sunday          10/24/2010        3
Saturday        10/23/2010        2
Friday          10/22/2010        0
Thursday        10/21/2010        0
Wednesday       10/20/2010        0

score 1 · Answer 3 · answered Nov 30 '08 at 22:24

Depending on how SQL Server handles temporary tables, you can more or less easily arrange to create a temporary table and populate it with the 7 (or was that 8?) dates you are interested in. You can then use that as your tally table. There isn't a cleaner way that I know of; you can only select data that exists in a table or that can be derived from data that exists in a table or set of tables. If there are dates not represented in the Orders table, you can't select those dates from the Orders table.

score 1 · Answer 4 · edited Dec 22 '11 at 18:56

1

If you want to see value zero than put the following query:

select count(*), sum(OrderAmount)
from Orders
where OrderDate>getdate()-7
  and sum(OrderAmount) > 0 or sum(OrderAmount) = 0
group by datepart(day,OrderDate)

edited Dec 22 '11 at 18:56

Brandon

68,708
30
194
223

answered Aug 21 '10 at 20:12

user427265

11
1
3

score 1 · Answer 5 · answered Dec 23 '10 at 13:37

CREATE PROCEDURE [dbo].[sp_Myforeach_Date]
    -- Add the parameters for the stored procedure here
    @SatrtDate as DateTime,
    @EndDate as dateTime,
    @DatePart as varchar(2),
    @OutPutFormat as int 
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    Declare @DateList Table
    (Date varchar(50))

    WHILE @SatrtDate<= @EndDate
    BEGIN
    INSERT @DateList (Date) values(Convert(varchar,@SatrtDate,@OutPutFormat))
    IF Upper(@DatePart)='DD'
    SET @SatrtDate= DateAdd(dd,1,@SatrtDate)
    IF Upper(@DatePart)='MM'
    SET @SatrtDate= DateAdd(mm,1,@SatrtDate)
    IF Upper(@DatePart)='YY'
    SET @SatrtDate= DateAdd(yy,1,@SatrtDate)
    END 
    SELECT * FROM @DateList
END

Just put this Code and call the SP in This way

exec sp_Myforeach_Date @SatrtDate='03 Jan 2010',@EndDate='03 Mar 2010',@DatePart='dd',@OutPutFormat=106

Thanks *Suvabrata Roy ICRA Online Ltd. Kolkata*

score 0 · Answer 6 · answered Dec 01 '08 at 22:07

0

Since you will want to use this date table frequently in other queries as well, I suggest you make it a permanent table and create a job to add the new year's dates once a year.

answered Dec 01 '08 at 22:07

HLGEM

94,695
15
113
186

1

Or fill it once with 20 years' dates. Trivial size, and why worry about the job. Next year it won't run and he'll be gone..... – dkretz Dec 01 '08 at 22:10

SQL group by day, show orders for each day

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