error: 'noexcept' does not name a type

Asked Oct 01 '15 at 14:31

Active Oct 01 '15 at 14:31

Viewed 2,739 times

Seems like it never happened to anyone so I guess I'm doing something wrong... The error I get is:

error: expected ';' at end of member declaration
error: 'noexcept' does not name a type

the code is this:

void* operator new (size_t size) noexcept
    {return foo(size);}

also the code is in macro actually, if it matters.

Thanks!

asked Oct 01 '15 at 14:31

user3445972

7

is the C++11 mode enabled? – Piotr Skotnicki Oct 01 '15 at 14:34
Have you defined -std=... ? – Andrey Derevyanko Oct 01 '15 at 14:34
Show your compiler command line, please. – Angew is no longer proud of SO Oct 01 '15 at 14:38
It's a big project so I'm not sure I'm looking at the right makefiles. I will check that out and let you know if it was that. Thank you – user3445972 Oct 01 '15 at 14:43
Seems you are forced to use older C++ standard. Try `throw()` instead of `noexcept`. – Andrey Nasonov Oct 01 '15 at 14:48

0 Answers0