So I know how to make it, I just want it to open the file without specifying the path.
For example: I have it in
C:\Users\\(me)\Desktop\Projects\BCs\BSCV2\bin\Debug\BSC.exe
but if I give it to a friend, he has a different username, (him)
for example, so the command won't be able to execute even if he has it on his desktop because the path isn't valid anymore.
Here's a part of the code:
#include <iostream>
#include <windows.h>
using namespace std;
int main()
{
int a;
cout << endl;
cout << " This window is used for launching the programs." << endl;
cout << " Type in the number of the program you want to use and press Enter." << endl;
cout << endl;
cout << " 1) BSCV2 << endl;
cout << endl;
cout << " "; cin >> a; cout << endl;
cout << endl;
if (a == 1){
system ("start C:\\Users\\(me)\\Desktop\\Projects\\BCs\\BSCV2\\bin\\Debug\\BSCV2.exe");
system ("pause");
}
return 0;
}
How can I make it run on anyone's PC, regardless of where they put it? Also, if you could re-write my code as an example, I'd appreciate it.